Call by Value function

Write a C++ program to find the value of a number raised to its power that demonstrates a function using call by value.

Algorithm to solve the above problem:

1) Start the program.

2) Declare the variables.

3) Get two numbers as input

4) Call the function power to which a copy of the two variables is passed .

5) Inside the function, calculate the value of x raised to power y and store it in p.

6) Return the value of p to the main function.

7) Display the result.

8) Stop the program.

Implementation of the above problem in C++:

#include<iostream>

using namespace std;

int main()

{

int x,y;

double power(int, int);

cout<<"Enter X and Y :"<<endl;

cin>>x>>y;

cout<<x<<" to the power "<<y <<" is "<< power(x,y);

return 0;

}

double power(int x, int y)

{

double p;

p=1.0;

if(y>=0)

{

while(y--)

p=p*x;

}

else

{

while(y++)

p=p/x;

}

return(p);

}

The output of the above program is tested on www.jdoodle.com

Output:

Enter X and Y :

4   3

4 to the power 3 is 64

Thanks

Mukesh Rajput