Leap Year or not

In the Mini project, next module is to check whether a given year is the leap year or not. Rita allotted this function to Johnny. Rita gave a hint about leap year conditions to Johnny.

Hint:

In general terms, the algorithm for calculating a leap year is as follows...

A year will be a leap year if it is divisible by 4 but not by 100. If a year is divisible by 4 and by 100, it is not a leap year unless it is also divisible by 400.

Thus years such as 1996, 1992, 1988 and so on are leap years because they are divisible by 4 but not by 100. For century years, the 400 rule is important. Thus, century years 1900, 1800 and 1700 while all still divisible by 4 are also exactly divisible by 100. As they are not further divisible by 400, they are not leap years.

Help Johnny to write a program to check whether a given year is a leap year or not?

Function Specification:

int leapyear(int year);

The function returns 1 if it is the leap year, else it returns 0.

Input Format:

Input consists of a single integer.

Output Format:

The output consists of a single line.

Refer sample input and output for formatting details.

Sample Input 1:

1988

Sample Output 1:

1988 is a leap year

Sample Input 2:

1994

Sample Output 2:

1994 is not a leap year

Program Code:

#include <stdio.h>

int leapyear (int year) 

{

if(year%4 == 0)

{

if( year%100 == 0)

{

// year is divisible by 400, hence the year is a leap year

if ( year%400 == 0)

return 1;

else

return 0;

}

else

return 1;

}

else

return 0;

}

int main()

{

int year,k;

scanf("%d",&year);

k=leapyear(year);

if(k==1)

printf("%d is a leap year",year);

else

printf("%d is not a leap year",year);

return 0;

}